<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-20592197711418287</id><updated>2012-02-15T23:31:41.777-08:00</updated><title type='text'>VICKYBLOG</title><subtitle type='html'></subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://vickyhseblog.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20592197711418287/posts/default?max-results=100'/><link rel='alternate' type='text/html' href='http://vickyhseblog.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>vickyblog</name><uri>http://www.blogger.com/profile/16026279743120066556</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>1</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>100</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-20592197711418287.post-5328987031506133221</id><published>2008-02-20T18:44:00.000-08:00</published><updated>2008-02-20T19:05:35.493-08:00</updated><title type='text'>1+1=1????</title><content type='html'>Si amigos aunque no lo crean asi es 1+1=1&lt;br /&gt;Esta es una propiedad que podemos encontra en el algebra booleana.&lt;br /&gt;Un algebra booleana consiste en un conjunto  S que contiene 2 elementos distintos, el 0 y el 1, operadores binarios + y . en S, y un  operdaor unario ' en S, los cuales cumplen las siguientes propiedades.&lt;br /&gt;leyes asociativas (x+y)+z=x+(y+z) para todo x, y, z que pertenecen a S&lt;br /&gt;                               (x.y).z=x.(y.z)&lt;br /&gt;leyes conmutativas  x+y=y+x           x.y=y.x&lt;br /&gt;leyes distributivas   x.(y+z)=(x.y)+(x.z)&lt;br /&gt;                                    x+(y.z)=(x+y).(x+z)&lt;br /&gt;leyes de indetidad  x+0=x      x.1=x para toda x que pertenece a S&lt;br /&gt;leyes de complementacion  x+x'=1         x.x'=0&lt;br /&gt;al elemento x' en un algebra booleana se le llama complemento de  x.&lt;br /&gt;&lt;br /&gt;si B es un algebra booleana  B=(s.+,.,',0,1) las siguientes propiedades se cumplen.&lt;br /&gt;leyes de idempotencia  X+X=X       X.X=X&lt;br /&gt;leyes de acotacion    x+1=1     x.0=0&lt;br /&gt;leyes de absorcion   x+x.y=x   x.(x+y)=x&lt;br /&gt;leyes de involucion (x')'=x&lt;br /&gt;leyes para el 0 y el 1    0'=1   1'=0&lt;br /&gt;las leyes son para toda  x que pertenece a B &lt;div&gt;leyes de morgan (x+y)'=x'.y'    (x.y)'=x'+y'&lt;/div&gt;&lt;br /&gt;si ahora observamos muy bien las leyes  de idempotencia en la primera vemos x+x=x&lt;br /&gt;si 1 pertenece al algebra booleana entonces 1+1=1.&lt;br /&gt;&lt;br /&gt;Demostracion:&lt;br /&gt;&lt;br /&gt;1=1+0&lt;br /&gt;1=1+(1.1')&lt;br /&gt;1=(1+1)(1+1')&lt;br /&gt;1=(1+1)1&lt;br /&gt;1=1+1&lt;br /&gt;&lt;br /&gt;no que no??&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20592197711418287-5328987031506133221?l=vickyhseblog.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://vickyhseblog.blogspot.com/feeds/5328987031506133221/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20592197711418287&amp;postID=5328987031506133221' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20592197711418287/posts/default/5328987031506133221'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20592197711418287/posts/default/5328987031506133221'/><link rel='alternate' type='text/html' href='http://vickyhseblog.blogspot.com/2008/02/111.html' title='1+1=1????'/><author><name>vickyblog</name><uri>http://www.blogger.com/profile/16026279743120066556</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry></feed>
